Compute voltage from current and resistance: if 750 µA flows through an 11 kΩ resistor, find the voltage drop across the resistor (report in volts).

Introduction / Context:
Small currents through kilo-ohm resistors often appear in sensing and instrumentation circuits. Converting microamperes and kilo-ohms correctly avoids large errors when applying Ohm’s law to compute voltage drop.

Given Data / Assumptions:

• I = 750 µA = 750 × 10^-6 A = 0.00075 A.
• R = 11 kΩ = 11 × 10^3 Ω = 11,000 Ω.
• Use V = I * R.

Concept / Approach:

Ensure consistent SI units before multiplying. Using exponent notation provides a quick sanity check and reduces decimal-placement errors.

Step-by-Step Solution:

Verification / Alternative check:

Power check: P = V * I = 8.25 * 0.00075 ≈ 0.00619 W ≈ 6.2 mW, a reasonable dissipation for typical small-signal resistors.

Why Other Options Are Wrong:

82.5 V and 146 V are too large for microampere currents; 14.6 V corresponds to different I–R values and not the given pair.

Common Pitfalls:

Failing to convert µA to A or kΩ to Ω; misplacing decimal points; rounding prematurely before completing the multiplication.

Final Answer:

8.25 V