Microampere estimation: Approximately how much current flows through a 3.3 MΩ resistor connected across a 30 V source?

Difficulty: Easy

Correct Answer: 9 µA

Explanation:


Introduction / Context:
High-value resistors with modest voltages produce microampere-level currents. Estimating these currents is essential for leakage calculations, bias networks, and battery life projections in low-power designs.


Given Data / Assumptions:

  • Resistance R = 3.3 MΩ = 3.3 × 10^6 Ω.
  • Voltage V = 30 V.
  • Need current magnitude I in microamperes.


Concept / Approach:
Ohm’s law gives I = V / R. Converting megaohms to ohms keeps arithmetic consistent; the expected answer is in the microampere range because V is in tens and R is in millions of ohms.


Step-by-Step Solution:

Compute I = V / R = 30 / (3.3 × 10^6) A.Do the division: 30 / 3.3 ≈ 9.09.Attach the scale: 9.09 × 10^-6 A = 9.09 µA ≈ 9 µA.


Verification / Alternative check:
Use the handy rule I(µA) ≈ V / R(MΩ). Here 30 / 3.3 ≈ 9.09 µA, which matches the computed value exactly, confirming the microampere estimate.


Why Other Options Are Wrong:

  • 90 µA: Would require R ≈ 0.33 MΩ, ten times smaller.
  • 900 µA: Corresponds to R ≈ 33 kΩ, far from 3.3 MΩ.
  • 9000 µA: Implies R ≈ 3.3 kΩ, not megaohms.


Common Pitfalls:

  • Confusing MΩ with kΩ and producing milliampere values by mistake.
  • Not converting to microamperes after obtaining the ampere value.


Final Answer:
9 µA

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