Microampere estimation: Approximately how much current flows through a 3.3 MΩ resistor connected across a 30 V source?
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A9 µA
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B90 µA
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C900 µA
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D9000 µA
Answer
Correct Answer: 9 µA
Explanation
Introduction / Context:High-value resistors with modest voltages produce microampere-level currents. Estimating these currents is essential for leakage calculations, bias networks, and battery life projections in low-power designs.
Given Data / Assumptions:
- Resistance R = 3.3 MΩ = 3.3 × 10^6 Ω.
- Voltage V = 30 V.
- Need current magnitude I in microamperes.
Concept / Approach:Ohm’s law gives I = V / R. Converting megaohms to ohms keeps arithmetic consistent; the expected answer is in the microampere range because V is in tens and R is in millions of ohms.
Step-by-Step Solution:
Compute I = V / R = 30 / (3.3 × 10^6) A.Do the division: 30 / 3.3 ≈ 9.09.Attach the scale: 9.09 × 10^-6 A = 9.09 µA ≈ 9 µA.Verification / Alternative check:Use the handy rule I(µA) ≈ V / R(MΩ). Here 30 / 3.3 ≈ 9.09 µA, which matches the computed value exactly, confirming the microampere estimate.
Why Other Options Are Wrong:
- 90 µA: Would require R ≈ 0.33 MΩ, ten times smaller.
- 900 µA: Corresponds to R ≈ 33 kΩ, far from 3.3 MΩ.
- 9000 µA: Implies R ≈ 3.3 kΩ, not megaohms.
Common Pitfalls:
- Confusing MΩ with kΩ and producing milliampere values by mistake.
- Not converting to microamperes after obtaining the ampere value.
Final Answer:9 µA