Ruling gradient and reduction in vehicle load capacity: choose the correct percentage reduction corresponding to the stated gradient.

Difficulty: Easy

Correct Answer: For 1 in 10, reduction is 10%

Explanation:


Introduction / Context:
On upgrades, the tractive effort available must overcome grade resistance. A practical thumb rule used in transport engineering is that the percentage reduction in load capacity is approximately equal to the grade (rise per 100) for moderate slopes.



Given Data / Assumptions:

  • Ruling gradient options: 1 in 10, 1 in 15, 1 in 20, 1 in 25.
  • Assume moderate speeds and typical commercial vehicles.
  • Reduction in load capacity roughly equals the grade percentage.


Concept / Approach:
Grade 1 in n corresponds to a slope of (1/n). As a percentage, this is (100/n)%. The reduction in load capacity is approximated by this percentage for quick checks in highway planning.



Step-by-Step Solution:

For 1 in 10: percentage grade = 100/10 = 10% → reduction ≈ 10%.For 1 in 15: percentage grade ≈ 6.67%, not 15%.For 1 in 20: percentage grade = 5%, not 10%.For 1 in 25: percentage grade = 4%, not 25%.


Verification / Alternative check:
The rule aligns with grade resistance per tonne being proportional to the slope, so doubling n halves the approximate percent reduction.



Why Other Options Are Wrong:
They misinterpret the reduction as equal to n instead of 100/n, leading to unrealistic high reductions for gentle grades.



Common Pitfalls:
Confusing “1 in n” with “n percent”; forgetting that percent grade is (100/n)%.



Final Answer:
For 1 in 10, reduction is 10%

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