Longest Rod Across a Rectangular Park — Diagonal Length: A park measures 10 m by 8 m. What is the length of the longest pole (rod) that can be placed flat inside the park?

Difficulty: Easy

Correct Answer: 12.8 metres

Explanation:


Introduction / Context:
The longest straight object that can fit inside a rectangle lies along its diagonal. Therefore, the maximum pole length equals the rectangle's diagonal obtained by the Pythagorean theorem using the side lengths as perpendicular legs.



Given Data / Assumptions:

  • Length = 10 m
  • Breadth = 8 m
  • Right-angle corner implies Pythagoras applies


Concept / Approach:
For a rectangle with sides a and b, the diagonal d satisfies d^2 = a^2 + b^2. Compute the square root of the sum of squares to find d. This geometric maximum is independent of object orientation as any longer orientation would exceed the rectangle's bounds.



Step-by-Step Solution:

Compute squares: 10^2 = 100; 8^2 = 64.Sum: 100 + 64 = 164.Diagonal: d = √164 ≈ 12.806… m ≈ 12.8 m to one decimal place.


Verification / Alternative check:

Compare alternatives: 12 m is too short (12^2 = 144 < 164); 13.4 m is too long (13.4^2 = 179.56 > 164).


Why Other Options Are Wrong:

  • 10 m equals one side, not the diagonal.
  • 18 m far exceeds the rectangular dimension constraints.
  • 12 m underestimates the true diagonal length.


Common Pitfalls:

  • Forgetting that the diagonal is longer than either side but not longer than the hypotenuse computed via Pythagoras.
  • Rounding early; carry enough precision before final rounding.


Final Answer:
12.8 metres.

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