Effect of Doubling Diameter on Circle Area — Percent Increase: If the diameter of a circle is increased by 100% (i.e., doubled), by what percent does its area increase?

Difficulty: Easy

Correct Answer: 300%

Explanation:


Introduction / Context:
Circle area depends on the square of a linear dimension (radius or diameter). Doubling the diameter doubles the radius as well, so the area multiplies by 2^2 = 4. Converting that factor to a percentage increase distinguishes absolute area from relative change.



Given Data / Assumptions:

  • Original diameter D; new diameter = 2D
  • Original radius r = D/2; new radius r' = D
  • Area formula: A = πr^2


Concept / Approach:
Compute the factor by which area changes: A'/A = (r'^2)/(r^2) = (D^2)/(D^2/4) = 4. A factor of 4 corresponds to a 300% increase because Increase% = (new − old)/old * 100% = (4A − A)/A * 100% = 300%.



Step-by-Step Solution:

Original area A = π(D/2)^2 = πD^2/4.New area A' = π(D)^2 = πD^2.Ratio A'/A = (πD^2) / (πD^2/4) = 4 ⇒ Increase% = (4 − 1)*100% = 300%.


Verification / Alternative check:

Numeric example: Let D = 10 ⇒ A = 78.54. New D = 20 ⇒ A' = 314.16. Increase = 235.62 ≈ 300% of 78.54.


Why Other Options Are Wrong:

  • 100% implies doubling area, not quadrupling.
  • 200% implies tripling total, still short of 4A.
  • 400% confuses new area with the percent increase.
  • 150% is arbitrary and unsupported.


Common Pitfalls:

  • Reporting the new area as 400% instead of the increase of 300%.


Final Answer:
300% increase.

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