Impedance of an RC series circuit: Is it correct that the magnitude of impedance is (R^2 + Xc^2)^(1/2), where Xc = 1 / (2 * pi * f * C), rather than (R^2 + C^2)^(1/2)?

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Impedance generalizes resistance to AC by incorporating phase and frequency dependence. For a series RC, the impedance vector is Z = R − j * Xc. Confusing the capacitance C (in farads) with the capacitive reactance Xc (in ohms) leads to dimensional errors and wrong results.


Given Data / Assumptions:

  • Sinusoidal steady state at frequency f.
  • Ideal R and C elements.
  • Magnitude operation on complex impedance.


Concept / Approach:
Capacitive reactance is Xc = 1 / (2 * pi * f * C). The series impedance is Z = R − j * Xc. The magnitude is |Z| = sqrt(R^2 + Xc^2). Substituting C directly into sqrt(R^2 + C^2) is incorrect because C has units of farads, not ohms. Proper dimensional analysis reinforces the correct formula.


Step-by-Step Solution:

Write Z = R − j * (1 / (2 * pi * f * C)).Compute |Z| = sqrt(R^2 + (1 / (2 * pi * f * C))^2).Note the unit consistency: both terms under the square root are in ohms squared.Conclude that (R^2 + C^2)^(1/2) is dimensionally and numerically wrong.


Verification / Alternative check:
Phasor diagrams and impedance triangles used in laboratory measurements match the sqrt(R^2 + Xc^2) expression and produce correct current and phase predictions.


Why Other Options Are Wrong:

Conditional statements (high frequency, R = 0, specific capacitor types) do not change the fundamental formula.


Common Pitfalls:
Plugging capacitance directly where reactance belongs; forgetting the frequency dependence of Xc.


Final Answer:
Correct

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