Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:
Signal-processing terms often come directly from mathematical operations. An “integrator” produces an output proportional to the time integral of the input. In electronics, RC and op-amp circuits implement this operation over a bandwidth, hence the name. The question probes whether the term is rooted in calculus or trigonometry.
Given Data / Assumptions:
Concept / Approach:
Integration is a calculus operation (antiderivative/area under a curve). While sinusoids are convenient test signals and appear in trigonometry, the integrator's definition does not rely on trigonometric identities; it is defined by the operator s^−1 in Laplace terms. RC and active integrators realize transfer functions proportional to 1/(RC s) in the intended region.
Step-by-Step Solution:
Verification / Alternative check:
Textbooks present the integrator via differential equations and Laplace transforms. Trigonometric test signals aid analysis but do not define the operator itself.
Why Other Options Are Wrong:
Incorrect: contradicts standard mathematical origin.
Depends on sinusoidal waveforms: the operator applies to any input, not just sinusoids.
Only true for digital integrators: both analog and digital integrators stem from the same calculus concept.
Common Pitfalls:
Confusing the prevalence of sine waves in testing with the mathematical source of the term; equating “integrator” with “low-pass filter” without specifying operating region.
Final Answer:
Correct
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