Terminology origin: The term “integrator” used for certain RC/operational-amplifier circuits derives from calculus (integration), not from trigonometry. Is this statement accurate?

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Signal-processing terms often come directly from mathematical operations. An “integrator” produces an output proportional to the time integral of the input. In electronics, RC and op-amp circuits implement this operation over a bandwidth, hence the name. The question probes whether the term is rooted in calculus or trigonometry.


Given Data / Assumptions:

  • Linear time-invariant system behavior within a frequency range.
  • Integrator approximates y(t) = ∫ x(t) dt scaled by a constant.
  • We refer to continuous-time integration from calculus.


Concept / Approach:
Integration is a calculus operation (antiderivative/area under a curve). While sinusoids are convenient test signals and appear in trigonometry, the integrator's definition does not rely on trigonometric identities; it is defined by the operator s^−1 in Laplace terms. RC and active integrators realize transfer functions proportional to 1/(RC s) in the intended region.


Step-by-Step Solution:

Define integrator: output proportional to the integral of the input. Connect to math: integral is a calculus construct. Relate to circuits: ideal transfer H(s) ∝ 1/s; practical RC/op-amp approximations implement this over a band. Conclude: the term originates from calculus, not trigonometry.


Verification / Alternative check:
Textbooks present the integrator via differential equations and Laplace transforms. Trigonometric test signals aid analysis but do not define the operator itself.


Why Other Options Are Wrong:
Incorrect: contradicts standard mathematical origin.
Depends on sinusoidal waveforms: the operator applies to any input, not just sinusoids.
Only true for digital integrators: both analog and digital integrators stem from the same calculus concept.


Common Pitfalls:
Confusing the prevalence of sine waves in testing with the mathematical source of the term; equating “integrator” with “low-pass filter” without specifying operating region.


Final Answer:
Correct

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