Difficulty: Medium
Correct Answer: Correct
Explanation:
Introduction / Context:
An “RC integrator” is a foundational analog building block used for pulse shaping, ramp generation, and as part of active filter designs. The classic passive form is a series R followed by a capacitor to ground, with output across the capacitor. Under the right frequency conditions, its output approximates the integral of the input waveform.
Given Data / Assumptions:
Concept / Approach:
The transfer function of the passive network is H(s) = 1 / (1 + s R C). For frequencies well above f_c, the magnitude of H(s) becomes small and the capacitor voltage approximates the time integral of the input scaled by 1/(R C). Step inputs yield exponential ramps initially; narrow pulses produce proportional area at the output, which is the essence of integration over the pulse width.
Step-by-Step Solution:
Verification / Alternative check:
Time-domain check: for a narrow input pulse of area A (volt-seconds), the change in capacitor voltage ΔV ≈ A / (R C), consistent with integration of the input.
Why Other Options Are Wrong:
Incorrect: contradicts the standard asymptotic behavior.
“Only true if R << Xc at all frequencies”: condition is frequency-dependent; at high f, |Xc| becomes small and the approximation holds.
“Only true when the input is DC”: integration of DC produces a ramp until limited; the integrator definition is broader and frequency-domain based.
Common Pitfalls:
Assuming perfect integration at any frequency; ignoring output amplitude droop and finite RC leakage; forgetting loading effects that spoil the ideal 1/s response.
Final Answer:
Correct
Discussion & Comments