Difficulty: Easy
Correct Answer: False
Explanation:
Introduction / Context:
First-order RC filters are ubiquitous. Getting the node selection right (where the output is measured) is crucial for identifying whether a circuit is low-pass or high-pass, and for predicting the phase shift between input and output.
Given Data / Assumptions:
Concept / Approach:
For the low-pass configuration, the transfer function is H(jω) = 1 / (1 + jωRC). Its phase is ∠H = −arctan(ωRC), a lagging phase (negative) that approaches −90° at high frequency. Taking output across the resistor instead produces a high-pass filter, not a low-pass.
Step-by-Step Solution:
Verification / Alternative check:
Swap the output node to be across R: H_hp(jω) = jωRC / (1 + jωRC), which is a high-pass response with phase lead at low frequencies. This confirms that the statement associating low-pass with output across R is incorrect.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing where to probe the output and misinterpreting phase lead versus lag. Remember: RC low-pass → output across C (lag); RC high-pass → output across R (lead).
Final Answer:
False
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