RC high-pass topology and phase behavior For a standard RC high-pass filter (series capacitor, shunt resistor), is the output taken across the resistor and does the output lead the input in phase for much of the spectrum?

Electrical Engineering Passive Filters Difficulty: Easy
Choose an option
  • A
    True
  • B
    False
  • C
    True only above the cutoff frequency
  • D
    True only for ideal components
  • E
    False unless the resistor is much larger than the capacitive reactance

Answer

Correct Answer: True

Explanation

Introduction / Context:Knowing where to measure the output in first-order filters is the key to predicting both magnitude and phase behavior. The RC high-pass places the capacitor in series and the resistor to ground, with the output across the resistor.

Given Data / Assumptions:

  • Series capacitor C, shunt resistor R to ground.
  • Output node is the junction between C and R (across R).
  • Transfer function: H(jω) = jωRC / (1 + jωRC).

Concept / Approach:

The magnitude of H rises from near 0 at very low frequency to ~1 at high frequency (20 dB/decade slope). The phase is positive (lead) at low frequency, approaching +90°, and tends to 0° at high frequency, meaning the output generally leads the input except in the asymptotic high-frequency limit.

Step-by-Step Solution:

Write H(jω) = jωRC / (1 + jωRC).Magnitude: |H| = (ωRC) / sqrt(1 + (ωRC)^2).Phase: ∠H = 90° − arctan(ωRC), which is a positive angle (lead) for finite ω.Therefore, output is across R and exhibits phase lead relative to input over most of the band.

Verification / Alternative check:

At ω = 1 / RC, |H| = 1 / sqrt(2) ≈ 0.707 and phase = +45°, a clear lead. At ω → ∞, phase → 0°, consistent with diminishing lead as the passband flattens.

Why Other Options Are Wrong:

  • “False” contradicts the textbook topology and phase result.
  • “True only above cutoff” misses the fact that the phase lead is strongest below cutoff.
  • Component ideality and value ratios do not alter the qualitative behavior.

Common Pitfalls:

Swapping output node to the capacitor (which would create a low-pass) or assuming phase lag because many filters lag; here, the high-pass leads.

Final Answer:

True

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