RC high-pass topology and phase behavior For a standard RC high-pass filter (series capacitor, shunt resistor), is the output taken across the resistor and does the output lead the input in phase for much of the spectrum?
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ATrue
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BFalse
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CTrue only above the cutoff frequency
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DTrue only for ideal components
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EFalse unless the resistor is much larger than the capacitive reactance
Answer
Correct Answer: True
Explanation
Introduction / Context:Knowing where to measure the output in first-order filters is the key to predicting both magnitude and phase behavior. The RC high-pass places the capacitor in series and the resistor to ground, with the output across the resistor.
Given Data / Assumptions:
- Series capacitor C, shunt resistor R to ground.
- Output node is the junction between C and R (across R).
- Transfer function: H(jω) = jωRC / (1 + jωRC).
Concept / Approach:
The magnitude of H rises from near 0 at very low frequency to ~1 at high frequency (20 dB/decade slope). The phase is positive (lead) at low frequency, approaching +90°, and tends to 0° at high frequency, meaning the output generally leads the input except in the asymptotic high-frequency limit.
Step-by-Step Solution:
Write H(jω) = jωRC / (1 + jωRC).Magnitude: |H| = (ωRC) / sqrt(1 + (ωRC)^2).Phase: ∠H = 90° − arctan(ωRC), which is a positive angle (lead) for finite ω.Therefore, output is across R and exhibits phase lead relative to input over most of the band.Verification / Alternative check:
At ω = 1 / RC, |H| = 1 / sqrt(2) ≈ 0.707 and phase = +45°, a clear lead. At ω → ∞, phase → 0°, consistent with diminishing lead as the passband flattens.
Why Other Options Are Wrong:
- “False” contradicts the textbook topology and phase result.
- “True only above cutoff” misses the fact that the phase lead is strongest below cutoff.
- Component ideality and value ratios do not alter the qualitative behavior.
Common Pitfalls:
Swapping output node to the capacitor (which would create a low-pass) or assuming phase lag because many filters lag; here, the high-pass leads.
Final Answer:
True