Difficulty: Medium
Correct Answer: 1.32
Explanation:
Introduction / Context:
Machine-tool speed charts are typically laid out in a geometric progression so that a single gearbox covers a wide range of cutting conditions without leaving big gaps. For drilling, spindle speed n is inversely proportional to drill diameter D for a given cutting speed V. This question tests selection of the common ratio for a six-speed drilling machine to span diameters from 6.25 mm to 25 mm at a fixed V.
Given Data / Assumptions:
Concept / Approach:
Because n is proportional to 1/D, the ratio of extreme speeds equals the inverse ratio of extreme diameters. With z speeds in geometric progression, nmax = nmin * r^(z−1), where r is the common ratio. Solve for r from the required total range.
Step-by-Step Solution:
Compute the overall speed range: nmax / nmin = Dmax / Dmin = 25 / 6.25 = 4.Relate to geometric progression: r^(z−1) = r^5 = 4.Solve for r: r = 4^(1/5).Numerical value: 4^(1/5) ≈ 1.3195, which rounds to 1.32.
Verification / Alternative check:
If r = 1.32, then r^5 ≈ 1.32^5 ≈ 4.00, matching the required 4:1 speed range exactly, so the progression covers 6.25 to 25 mm properly.
Why Other Options Are Wrong:
1.02 gives an unrealistically fine progression (r^5 ≈ 1.10). 1.66 and 1.82 produce r^5 far exceeding 4, creating gaps. 1.41 gives r^5 ≈ 5.38, still too large a range.
Common Pitfalls:
Forgetting that speed varies as 1/D, using linear instead of geometric spacing, or mixing units (mm vs m) when computing absolute n. Here only ratios are needed, so unit consistency is implicit.
Final Answer:
1.32
Discussion & Comments