number-systems-and-codes digital-electronics question and answers -Page 15

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Number Systems and Codes problems

1. 12₁₀= 1101₂ = C₁₆ = 00010010 BCD
Options
A. True
B. False

Correct Answer: False

2. When converting from decimal to binary by the repeated division-by-two method, the initial remainder becomes the MSD.
Options
A. True
B. False

Correct Answer: False

3. A binary number can be converted to a decimal number by summing the decimal values of the weights of all the 1s in the binary number.
Options
A. True
B. False

Correct Answer: True

4. ASCII stands for American Standard Code for Information Interchange.
Options
A. True
B. False

Correct Answer: True

5. In ASCII code, the hexadecimal sequence 53 54 55 44 45 4E 54 decodes to STUDENT.
Options
A. True
B. False

Correct Answer: True

6. In odd parity, 100011010 would pass the parity check.
Options
A. True
B. False

Correct Answer: False

7. Repeated division-by-10 is used to convert decimal numbers to binary numbers.
Options
A. True
B. False

Correct Answer: False

8. The 2's complement of a binary number is derived by adding 1 to the 1's complement.
Options
A. True
B. False

Correct Answer: True

9. A decimal number is converted to BCD by replacing each decimal digit with the appropriate 3-bit binary code.
Options
A. True
B. False

Correct Answer: False

10. Binary-coded-decimal 0111 1001 0011 is ________ in binary.
Options
A. 011110010011
B. 010110101111
C. 001100110011
D. 001100011001

Correct Answer: 001100011001

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