Strings problems
- 1. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { static char str1[] = "dills"; static char str2[20]; static char str3[] = "Daffo"; int i; i = strcmp(strcat(str3, strcpy(str2, str1)), "Daffodills"); printf("%d\n", i); return 0; }
Options- A. 0
- B. 1
- C. 2
- D. 4 Discuss
Correct Answer: 0
- 2. If char=1, int=4, and float=4 bytes size, What will be the output of the program?
#include<stdio.h> int main() { char ch = 'A'; printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f)); return 0; }
Options- A. 1, 2, 4
- B. 1, 4, 4
- C. 2, 2, 4
- D. 2, 4, 8 Discuss
Correct Answer: 1, 4, 4
Explanation:
Step 2:
printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14));
The sizeof function returns the size of the given expression.
sizeof(ch) becomes sizeof(char). The size of char is 1 byte.
sizeof('A') becomes sizeof(65). The size of int is 4 bytes (as mentioned in the question).
sizeof(3.14f). The size of float is 4 bytes.
Hence the output of the program is 1, 4, 4
- 3. What will be the output of the program?
#include<stdio.h> int main() { char t; char *p1 = "India", *p2; p2=p1; p1 = "CURIOUSTAB"; printf("%s %s\n", p1, p2); return 0; }
Options- A. India CURIOUSTAB
- B. CURIOUSTAB India
- C. India India
- D. CURIOUSTAB CURIOUSTAB Discuss
Correct Answer: CURIOUSTAB India
Explanation:
Step 2: p2=p1; The value of p1 is assigned to variable p2. So p2 contains "India".
Step 3: p1 = "CURIOUSTAB"; The p1 is assigned with a string "CURIOUSTAB"
Step 4: printf("%s %s\n", p1, p2); It prints the value of p1 and p2.
Hence the output of the program is "CURIOUSTAB India".
- 4. What will be the output of the program?
#include<stdio.h> int main() { char str[] = "India\0CURIOUSTAB\0"; printf("%d\n", sizeof(str)); return 0; }
Options- A. 10
- B. 6
- C. 5
- D. 11 Discuss
Correct Answer: 11
Explanation:
1. sizeof("") returns 1 (1*).
2. sizeof("India") returns 6 (5 + 1*).
3. sizeof("CURIOUSTAB") returns 4 (3 + 1*).
4. sizeof("India\0CURIOUSTAB") returns 10 (5 + 1 + 3 + 1*).
Here '\0' is considered as 1 char by sizeof() function.
5. sizeof("India\0CURIOUSTAB\0") returns 11 (5 + 1 + 3 + 1 + 1*).
Here '\0' is considered as 1 char by sizeof() function.
- 5. What will be the output of the program?
#include<stdio.h> int main() { int i; char a[] = "\0"; if(printf("%s", a)) printf("The string is empty\n"); else printf("The string is not empty\n"); return 0; }
Options- A. The string is empty
- B. The string is not empty
- C. No output
- D. 0 Discuss
Correct Answer: The string is not empty
Explanation:
Step 1: char a[] = "\0"; The variable a is declared as an array of characters and it initialized with "\0". It denotes that the string is empty.
Step 2: if(printf("%s", a)) The printf() statement does not print anything, so it returns '0'(zero). Hence the if condition is failed.
In the else part it prints "The string is not empty".
- 6. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { printf("%d\n", strlen("123456")); return 0; }
Options- A. 6
- B. 12
- C. 7
- D. 2 Discuss
Correct Answer: 6
Explanation:
Therefore, strlen("123456") returns 6.
Hence the output of the program is "6".
- 7. What will be the output of the program in Turbo C?
#include<stdio.h> int main() { char str[10] = "India"; str[6] = "CURIOUSTAB"; printf("%s\n", str); return 0; }
Options- A. India CURIOUSTAB
- B. CURIOUSTAB
- C. India
- D. Error Discuss
Correct Answer: Error
Explanation:
- 8. What will be the output of the program?
#include<stdio.h> void swap(char *, char *); int main() { char *pstr[2] = {"Hello", "CuriousTab"}; swap(pstr[0], pstr[1]); printf("%s\n%s", pstr[0], pstr[1]); return 0; } void swap(char *t1, char *t2) { char *t; t=t1; t1=t2; t2=t; }
Options- A. CuriousTab
Hello - B. Address of "Hello" and "CuriousTab"
- C. Hello
CuriousTab - D. Iello
HndiaCURIOUSTAB
Discuss
Correct Answer: Hello
CuriousTab
Explanation:
Step 2: char *pstr[2] = {"Hello", "CuriousTab"}; The variable pstr is declared as an pointer to the array of strings. It is initialized to
pstr[0] = "Hello", pstr[1] = "CuriousTab"
Step 3: swap(pstr[0], pstr[1]); The swap function is called by "call by value". Hence it does not affect the output of the program.
If the swap function is "called by reference" it will affect the variable pstr.
Step 4: printf("%s\n%s", pstr[0], pstr[1]); It prints the value of pstr[0] and pstr[1].
Hence the output of the program is
Hello
CuriousTab
- 9. What will be the output of the program?
#include<stdio.h> int main() { static char mess[6][30] = {"Don't walk in front of me...", "I may not follow;", "Don't walk behind me...", "Just walk beside me...", "And be my friend." }; printf("%c, %c\n", *(mess[2]+9), *(*(mess+2)+9)); return 0; }
Options- A. t, t
- B. k, k
- C. n, k
- D. m, f Discuss
Correct Answer: k, k
- 10. What will be the output of the program in 16-bit platform (Turbo C under DOS)?
#include<stdio.h> int main() { printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0)); return 0; }
Options- A. 8, 1, 4
- B. 4, 2, 8
- C. 4, 2, 4
- D. 10, 3, 4 Discuss
Correct Answer: 4, 2, 8
Explanation:
printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));
The sizeof function returns the size of the given expression.
sizeof(3.0f) is a floating point constant. The size of float is 4 bytes
sizeof('3') It converts '3' in to ASCII value.. The size of int is 2 bytes
sizeof(3.0) is a double constant. The size of double is 8 bytes
Hence the output of the program is 4,2,8
Note: The above program may produce different output in other platform due to the platform dependency of C compiler.
In Turbo C, 4 2 8. But in GCC, the output will be 4 4 8.
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