What will be the output of the program? #include<stdio.h>
#include<string.h>
int main()
{
char *s;
char *fun();
s = fun();
printf("%s\n", s);
return 0;
}
char *fun()
{
char buffer[30];
strcpy(buffer, "RAM");
return (buffer);
}
Correct Answer: Garbage value
Explanation:
The output is unpredictable since buffer is an auto array and will die when the control go back to main. Thus s will be pointing to an array , which not exists.
