How many bytes of memory will the following code reserve? #include #include int main() { int *p; p = (int *)malloc(256 * 256); if(p == NULL) printf("Allocation failed"); return 0; }

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Accepted Answer

Hence 256*256 = 65536 is passed to malloc() function which can allocate upto 65535. So the memory allocation will be failed in 16 bit platform (Turbo C in DOS).

If you compile the same program in 32 bit platform like L…

How many bytes of memory will the following code reserve? #include<stdio.h> #include<stdlib.h> int main() { int p; p = (int )malloc(256 * 256); if(p == NULL) printf("Allocation failed"); return 0; }

Discussion & Comments

How many bytes of memory will the following code reserve? #include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(256 * 256); if(p == NULL) printf("Allocation failed"); return 0; }

Discussion & Comments

How many bytes of memory will the following code reserve? #include<stdio.h> #include<stdlib.h> int main() { int p; p = (int )malloc(256 * 256); if(p == NULL) printf("Allocation failed"); return 0; }