In C language, how will you treat the constant 3.14 explicitly as a float literal? Use the correct single-letter suffix that converts a double literal into a float.

Introduction:
This question tests how to specify the type of a floating constant directly in source code, ensuring it is compiled as a float rather than the default double.

Given Data / Assumptions:

• Literal: 3.14
• Target type: float
• Language: C, standard literal suffix rules

Concept / Approach:
Unadorned decimal floating constants are of type double. Appending the suffix 'f' or 'F' makes the literal type float. This avoids implicit conversions when initializing float variables or calling functions expecting float.

Step-by-Step Solution:
1) Start with 3.14 (double by default).2) Append the 'f' suffix to get 3.14f, which is type float.3) Use it directly in initializations like: float x = 3.14f;

Verification / Alternative check:
Use sizeof in a quick test expression or inspect warnings when assigning 3.14 versus 3.14f to a float; the suffixed form avoids promotions or conversions.

Why Other Options Are Wrong:
float(3.14f): 'float(...)' is not a cast syntax in C; C uses (type)expr. Also unnecessary if the literal already has 'f'.f(3.14): 'f' is not a type or function by default; this is not a suffix.(f)(3.14): 'f' is not a valid typename. Casts must use real types like (float).

Common Pitfalls:
Forgetting the suffix causes the compiler to treat the literal as double, which may change overload resolution in C++, or cause implicit conversions and warnings in C when assigned to float.

Final Answer:
use 3.14f