let the inner and outer radii be r and R meters
then,
= 352/7
=> r = (352/7) * (7/22) * (1/2) = 8m
= 528/7
=> R= (528/7) * (7/22) * (1/2)= 12m
width of the ring = R-r = 12-8 = 4m
side of first square = 40/4 =10cm
side of second square = 32/4 = 8cm
area of third squre = 10² - 8² = 36 sq cm
side of third square = = 6 cm
required perimeter = 6*4 = 24cm
area of the field grazed = (22/7) * 14 * 14 = 616 sq feet
let each wheel make x revolutions per sec. Then
distance moved by smaller wheel in 3 revolutions
=
speed of smaller wheel = m/s = 22m/s
Required ratio =
We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cm
Given perimeter of square is twice the perimeter of rectangle = 2(30) = 60cm
Therefore, side of the square is = 1/4 x 60 = 15cm
Circumference of the required semicircle =
=
= 23.57 + 15 = 38.57cm.
Length of the thread is 36 cms.
length wise twice breath wise once then totally thrice.
so 36/3 = 12.
so length is 12 x 2 = 24 cms
breath is 12 cms
Area of the book = length x breath = 24 x 12 = 288 sq.cm
speed of the man = 4 x (5/18) m/sec = 10/9 m/sec
time taken = 3 x 60 sec = 180 sec
length of diagonal = speed x time = (10/9) x 180 = 200m
Area of the field = (1/2) x (dioagonal)²
= (1/2) x 200 x 200 sq.m = 20000sq.m
let breadth = x then length = x+20
perimeter = 5300/26.50 = 200m
2(x+20+x) =200 => 4x+40 =200
x = 40 and length = 40+20 = 60m
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