Perimeter of a square p=4s ,where s=length of its side
=> p=4(14)=56 feets
Area of a square A = s x s
=> A=196
The perimeter is 56 feet, and the area is 196 square feet.
let each have base = b and height = h
then p = b*h, R = b*h and T = (1/2) * b*h
so P = R, P = 2T and T = (1/2)*R are all correct statements
let the side of the square be x meters
length of two sides = 2x meters
diagonal =
= 1.414x m
saving on 2x meters = .59x m
saving % = %
= 30% (approx)
A=LB
A = lw
Area to be plastered= [2(l + b) x h] + (l x b)
= [2(25 + 12) x 6] + (25 x 12)
= (444 + 300)
= 744 sq.m
Cost of plastering = Rs.744 x (75/100)
Let the inner and outer radii be r and R metres.
Then
=> Width of the ring = (R - r) = (12 - 8) m = 4 m.
let original radius = r and new radius = (50/100) r = r/2
original area =
and new area =
decrease in area =
*
*100 = 75%
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