M = 10 days
The ratio of efficiency of M & N are 3 : 2
Hence, the time rquired for N alone = 15 days
=> Required time taken t=by both to complete the work = M x N / M + N
= 10 x 15/ 10 + 15
= 150/25
= 6 days.
Efficiency of P= 100/20= 5% per hour
Efficiency of Q= 100/25= 4% per hour
Efficiency of R= 100/40= 2.5% per hour
Efficiency of S=100/50= 2% per hour
Cistern filled till 10 am by P, Q and R
Thus, at 10 am pipe P,Q and R filled 30.5% of the cistern.
Rest of cistern to be filled = 100 - 30.5 = 69.5%
Now, the time taken by P,Q,R and S together to fill the remaining capacity of the cistern
= 69.5 / (5+4+2.5+2) = 5 Hours and 9 minutes(approx).
Therefore, total time =4 hrs + 5hrs 9 mins = 9 hrs and 9 mins
It means cistern will be filled up at 3:09 pm
Ratio of times taken by P & Q = 100 : 130 = 10:13
Let Q takes x days to do the work
Then, 10:13 :: 23:x
=> x = 23x13/10
=> x = 299/10
P's 1 day's work = 1/23
Q's 1 day's work = 10/299
(P+Q)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13
Hence, P & Q together can complete the work in 13 days.
9M + 12B ----- 12 days ...........(1)
12M + 12B ------- 10 days........(2)
10M + 10B -------?
108M + 144B = 120M +120B
24B = 12M => 1M = 2B............(3)
From (1) & (3)
18B + 12B = 30B ---- 12 days
20B + 10B = 30B -----? => 12 days.
Days remaining 124 ? 64 = 60 days
Remaining work = 1 - 2/3 = 1/3
Let men required men for working remaining days be 'm'
So men required = (120 x 64)/2 = (m x 60)/1 => m = 64
Men discharge = 120 ? 64 = 56 men.
Given that three athletes can complete one round around a circular field in 16, 24 and 36 min respectively.
Now, required time after which they met for the first time = LCM of (16, 24 & 36) min
Now, LCM of 16, 24, 36 = 144 minutes = 2 hrs 24 min.
Total work = 100+50 = 150man-days
In 8 days 100 man-days work has been completed. Now on 9th and 10th day there will be 25 workers. So in 2 days they wll complete additional 50 man- days work. Thus the work requires 2 more days.
Now, Total work = LCM(16, 8) = 48
A's one day work = + 48/16 = + 3
B's one day work = - 48/8 = -6
Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15
2days B joined with A in working = 2(3 - 6) = - 6
Remaining Work of building wall = 48 - (15 - 6) = 39
Now this remaining work will be done by A in = 39/3 = 13 days.
From the given data,
Day Capacity
A -> 12 2
B -> 8 3 2
A + B + C -> 2 12
=> Capacity of C = 12 - 5 = 7
Ratio of capacity of A : B : C = 2 : 3 : 7
Difference of wages of C & B = 4/5 x 1540
= 4 x 308 = Rs. 1232
We know that Time is inversely proportional to Efficiency
Here given time ratio of P & P+Q as
P/P+Q = 150/100 = 3:2
Efficiency ratio of P & Q as
P:Q = 2:1 ....(1)
Given Efficiency ratio of Q & R as
Q:R = 3:1 ....(2)
From (1) & (2), we get
P:Q:R = 6:3:1
P alone can finish the work in
22.5(3+1)/6 = 15 days.
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