Let Q complete that work in 'L' days
=>
=>
L = 25 days.
Given X can do in 10 days
=> 1 day work of X = 1/10
Y can do in 15 days
=> 1 day work of Y = 1/15
1day work of (X + Y) = 1/10 + 1/15 = 1/6
Given they are hired for 5 days
=> 5 days work of (X + Y) = 5 x 1/6 = 5/6
Therefore, Unfinished work = 1 - 5/6 = 1/6
Given (3 Men + 4 Women + 6 Children) -----> 9 days
But W = 2M and C = M/2
Now, convert Men and Children into Women by
Therefore, 7 women alone can complete this work in 9 days.
Remaining work = 1 - 9/10 = 1/10
=> A & B together completes 1/10 of work in 4 days
=> 1 work can completed in ------ ? days
Let it be x days
=>
=> x = 40 days.
Hence, A & B together can complete the work in 40 days.
(20 x 18) men can complete the work in in one day.
one man's one day work = 1/360
(18 x 15) women can complete the work in 1 day
1 woman's one day work = 1/270
So, required ratio = = 4:3
(16M + 12W) x 20 = 18W x 40
=> 2M = 3W
Then,
Convert all men into women
12M + 27W = 27 + 12 x 3/2W = 45W
Let number of days required be 'D'
=> 18 x 40 = 45 x D
=> D = 16 days.
Rate of leakage = 8.33% per hour
Net efficiency = 50 - (16.66 + 8.33)= 25%
Time required = 100/25 = 4 hours
Clearly total persons are increased in 28/35 :: 52/65 = 4:5.
As time is inversely proportional to men, so total time will decrease in the ratio 5:4.
Hence, 22.5 x 4/5 = 18 days.
After 10 days, the remaining food would be sufficient for the 1000 students for 20 more days
-->If 1000 more students are added, it shall be sufficient for only 10 days (as the no. of students is doubled, the days are halved).
50 men can build a tank in 40 days
Assume 1 man does 1 unit of work in 1 day
Then the total work is 50×40 = 2000 units
50 men work in the first 10 days and completes 50×10 = 500 units of work
45 men work in the next 10 days and completes 45×10 = 450 units of work
40 men work in the next 10 days and completes 40×10 = 400 units of work
35 men work in the next 10 days and completes 35×10 = 350 units of work
So far 500 + 450 + 400 + 350 = 1700 units of work is completed and
Remaining work is 2000 - 1700 = 300 units
30 men work in the next 10 days. In each day, they does 30 units of work.
Therefore, additional days required = 300/30 =10
Thus, total 10+10+10+10+10 = 50 days required.
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