Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 7 x 11.
So, required number = 22 x 32 x 72 x 112 = 213444
What should come in place of both x in the equation | x | = | √162 | . |
√128 | x |
Let | x | = | √162 |
√128 | x |
Then x2 = √128 x 162
= √64 x 2 x 18 x 9
= √82 x 62 x 32
= 8 x 6 x 3
= 144.
∴ x = √144 = 12.
⟹ 3√5 + √25 x 5 = 17.88
⟹ 3√5 + 5√5 = 17.88
⟹ 8√5 = 17.88
⟹ √5 = 2.235
∴ √80 + 6√5 = √16 x 5 + 6√5
= 4√5 + 6√5
= 10√5 = (10 x 2.235) = 22.35
= √(1 - 2a)2 + 3a
= (1 - 2a) + 3a
= (1 + a)
= (1 + 0.1039)
= 1.1039
1|1.5625( 1.25 |1 |------- 22| 56 | 44 |------- 245| 1225 | 1225 |------- | X |-------∴ √1.5625 = 1.25.
In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
?y/169= 54/39
? y/169 = (54/39) x (54/39)
? y= (54/39) x (54/39) x 169 = 324
Given Expression 112/?196 x ?579/12 x ?256/8
=(112/14) x (24/12) x (16/8)
= 32
?4096 + ?40.96 + ?.004096
= ?4096 + ?4096/100 + ?4096/1000000
=?4096 + ?4096/10 + ?4096/1000
= 64 + 64/10 + 64/1000
= 70.464
?.04 = ?4/100
= 2/10
= 0.2
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