If x = √3 + 1 and y = √3 - 1 , then the value of (x2 + y2) is: √3 - 1 √3 + 1

Question

Accepted Answer

x = (√3 + 1) x (√3 + 1) = (√3 + 1)2 = 3 + 1 + 2√3 = 2 + √3. (√3 - 1) (√3 + 1) (3 - 1) 2 y = (√3 - 1) x (√3 - 1) = (√3 - 1)2 = 3 + 1 - 2√3 = 2 - √3. (√3 + 1) (√3 - 1) (3 - 1) 2 ∴ x2 + y2 = (2 + √3)2 + (2 - √3)2 = 2(4 + 3) = 14

If x = √3 + 1 and y = √3 - 1 , then the value of (x2 + y2) is: √3 - 1 √3 + 1

More Questions from Square Root and Cube Root

Discussion & Comments

x =	(√3 + 1)	x	(√3 + 1)	=	(√3 + 1)²	=	3 + 1 + 2√3	= 2 + √3.
	(√3 - 1)		(√3 + 1)		(3 - 1)		2

y =	(√3 - 1)	x	(√3 - 1)	=	(√3 - 1)²	=	3 + 1 - 2√3	= 2 - √3.
	(√3 + 1)		(√3 - 1)		(3 - 1)		2