Milk = 60 x (2/3) litres =40 litres
Water = (60 - 40) litres = 20 litres
? 40 / (20 + x) = 1/2
? 20 + x = 80
? x = 60
Hence water to be added = 60 litres.
? A : B = 2 : 3, B : C = 2 : 3 and C:D = 2 : 3
? A : B = 8 : 12, B : C = 12 : 18 and C : D = 18 : 27
? A : B : C : D =8 : 12 : 18 : 27
So A's share = Rs. 1300 x ( 8 / 65) = Rs. 160
First glass contains milk = 1/3 and water = 2/3
Second glass contains milk = 1/4 and water = 3/4
? Now tumbler contains water = (3/2 + 3/4) = 17/12
? Ratio of milk and water =7/12 : 17/12 =7 : 17
Let (a/b) = (c/d) = k
Then, a = bk and c = dk.
? (ma + nc) / (mb + nd) = (mbk + ndk) / (mb + nd) = k(mb + nd/mb + nd)
= k = a/b = a : b.
Let quantity of milk and water be 5x and x litres.
Then, 5x / (x + 5) = 5/2
? 10x = 5x + 25
? x =5
? Quantity of milk = 5x =25 litres
A : B = 4 : 5 = 8 : 10 and B : C = 2 : 3 = 10 : 15
? A : B : C = 8 : 10 :15
If A has Rs. 8, C has Rs. 15
If A has Rs. 800 C has Rs. (15/8 x 100) = Rs. 1500
Alcohol = (20/100) x 15 litres = 3 litres,
Water = 12 litres
New mix, contains,
Alcohol = 3 litres,
Water = 15 litres
? Percentage of alcohol in new mix. = (3/18) x 100 % = 162/ 3%
M = 3E and M/H = 4/3
? H = 3/4 M = 3/4 x 3E = 9/4 E
Now M + E + H = 250
? 3E + E + 9/4 E = 250
? 25 E = 1000
? E = 40
Let, 1 gm of gold be mixed with y gm of copper to give (1 +x) gm of mixture.
Now, 1G =19W and 1C = 9W and mixture = 15W
Now, 1 gm gold + y gm copper = (1 + y) gm mixture
? 19 W + 9W x y = (1 + y ) x 15W
Thus 4W = 6W x y
? y = 4W/6W = 4/6 = 2/3
So the required ratio is 1 : 2/3 i.e. 3 : 2
? 2A/5 + 40 = 2B/7 + 20 = 9C/17 + 10 = k
? A = 5(k - 40)/2, B =7(k - 20)/2 and C = 17(k - 10)/9
? 5(k - 40)/2 +7(k - 20)/2 +17/(k - 10 )/9 = 600
? 45k - 1800 + 63k - 1260 + 34k - 340 = 10800
? 142k = 14200
? k = 14200 / 142 = 100
Hence A's share = (5/2) x ( 100 - 40) = Rs. 150
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