Price difference resolves individual prices from a 3:2 ratio The prices of a scooter and a television set are in the ratio 3 : 2. If the scooter costs ₹ 6,000 more than the television, what is the television’s price?

Introduction / Context:
Price-ratio with a known difference lets us solve for individual prices. Let the common ratio multiplier be x and translate the difference into an equation in x, then compute each price.

Given Data / Assumptions:

• Scooter : Television = 3 : 2.
• Scooter costs ₹ 6,000 more.

Concept / Approach:
Let scooter = 3x and television = 2x. Then difference 3x − 2x = x = ₹ 6,000. Hence television = 2x = 2 * 6,000.

Step-by-Step Solution:
x = ₹ 6,000.Television price = 2x = 2 * 6,000 = ₹ 12,000.

Verification / Alternative check:
Then scooter = 3x = ₹ 18,000. The ratio 18,000 : 12,000 simplifies to 3 : 2 and the difference is ₹ 6,000, confirming correctness.

Why Other Options Are Wrong:
₹ 6,000 is the difference, not the TV price; ₹ 10,000 and ₹ 9,000 break the ratio-difference relationship; ₹ 18,000 is the scooter price, not the TV price.

Common Pitfalls:
Swapping which item is larger or treating 6,000 as one of the ratio parts rather than the difference of 1 part.

Final Answer:
Rs. 12000