Profit and Loss problems
- 1. At what price must Kantilal sell a mixture of 80 kg sugar at Rs. 6.75 per kg with 120 kg at Rs. 8 per kg to gain 20%?
Options- A. Rs. 7.50 per kg
- B. Rs. 8.20 per kg
- C. Rs. 8.85 per kg
- D. Rs. 8.76 per kg Discuss
Correct Answer: Rs. 8.76 per kg
Explanation:
Total C.P.of 200 kg of sugar = Rs. (80 x 6.75 + 120 x 8)
= Rs. (500 + 960)
= Rs. 1460
C.P. of 1 kg = Rs. 1460 / 200 = Rs. 7.30
Gain required = 20%
? S.P. of 1 kg = (120% of Rs. 7.30)
= Rs. (120/100) x 7.30
= Rs. 8.76 per kg
- 2. The percent profit when an article is sold for Rs. 78 is twice as when it is sold for Rs. 69. The C.P. of the article is?
Options- A. Rs. 49
- B. Rs. 51
- C. Rs. 57
- D. Rs. 60 Discuss
Correct Answer: Rs. 60
Explanation:
Let the C.P. be Rs. x
Then 2(69 - x) / 100 = (78 - x) / 100
? 138 - 2x = 78 - x
? x = 60
? C.P. = Rs. 60
- 3. A trader by means of a false balance defrauder to the extent of 8% in buying goods and also defrauds to 8% in selling. His gain percent is?
Options- A. 15.48%
- B. 16%
- C. 16.64%
- D. None of these Discuss
Correct Answer: 16.64%
Explanation:
In such question we adopt the Required gain %
= [(100 + common gain%)2 / 100 - 100] %
= { (108)2/100 - 100 } % = 16.64%
- 4. Kabir buys an article with 25% discount on its marked price. He makes a profit of 10% by selling it at Rs. 660. The marked price is?
Options- A. Rs. 600
- B. Rs. 700
- C. Rs. 800
- D. Rs. 685 Discuss
Correct Answer: Rs. 800
Explanation:
Let the marked price be Rs. N
? C.P. = (N - 25% of N) = 3N / 4
? S.P. = (3N / 4 + 10% of 3N / 4) = 33N / 40
But, 33N / 40 = 660
? N = 800
- 5. A discount series of 10%, 20% and 40% is equal to a single discount of?
Options- A. 50%
- B. 56.8%
- C. 60%
- D. 70.28% Discuss
Correct Answer: 56.8%
Explanation:
Let original price = Rs. 100
Price after first discount = Rs. 90
Price after second discount = Rs. (80 x 90)/100 = Rs. 72
Price after third discount = Rs. (60 x 72)/100 = Rs. 43.20
? Single equivalent discount = (100 - 43.20) = 56.8%
- 6. The ratio of the prices of three different types of cars is 4 : 5 : 7. If the difference between the costliest and the cheapest cars is Rs. 60000 the price of the car of modest price is?
Options- A. Rs. 80, 000
- B. Rs. 1, 00, 000
- C. Rs. 1,40, 000
- D. Rs. 1,20, 000 Discuss
Correct Answer: Rs. 1, 00, 000
Explanation:
Let the price of be 4x, 5x and 7x rupees.
Then, 7x - 4x = Rs. 60000
? x = 20000
? Required modest price = 5x = Rs. 100000
- 7. A man purchases an electric heater whose printed price is Rs. 160. If he received two successive discounts of 20% and 10% he paid?
Options- A. Rs. 112
- B. Rs. 129.60
- C. Rs. 119.60
- D. Rs. 115.20 Discuss
Correct Answer: Rs. 115.20
Explanation:
Price after 1 st discount = 80% of Rs. 160 = Rs. 128
Price after 2nd discount = 90% of Rs. 128 = Rs. 115.20
- 8. A trader lists his articles 20% above C.P. and allows a discount of 10% on cash payment. His gain per cent is?
Options- A. 10%
- B. 8%
- C. 6%
- D. 5% Discuss
Correct Answer: 8%
Explanation:
Let C.P. = Rs. 100
Then marked price = Rs. 120
S.P. = 90% of Rs. 120 = Rs. 108
? Required gain% = {(108 - 100) / 100} x 100% = 8%
- 9. The difference between a discount of 40% on Rs. 500 and two successive discount of 36% and 4% on the same amount is?
Options- A. 0
- B. Rs. 2
- C. Rs. 1.93
- D. Rs. 7.20 Discuss
Correct Answer: Rs. 7.20
Explanation:
Sale after 40% discount = 60% of Rs. 500 = Rs. 300
Price after 36% discount = 64% of Rs. 500 = Rs. 320
Price after next 4% discount = 96% of Rs. 320 = Rs. 307.20
? Required difference in two prices = (307.20 - 300) = Rs. 7.20
- 10. By selling 45 oranges for Rs. 40, a man loss 20%. how many should he sell for Rs. 24 so as to gain 20% in the transaction?
Options- A. 16
- B. 18
- C. 20
- D. 22 Discuss
Correct Answer: 18
Explanation:
Cost price for 45 oranges - 20% = Rs. 40.
? Cost price for 45 oranges = Rs. 50.
When he sells for Rs. 24 his gain is 20%, hence cost price is Rs 20.
Number of oranges = (20 x 45)/50 = 18
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