First train leaves at 8 :00 am and second at 9:00 am.
So, first train i,e from P to Q has covered 25 km distance in 1 h.
So, distance left between the station = 145 - 25 = 120 km
Now, trains are travelling in opposite directions,
So, relative speed = 25 + 35 = 60 km/h
Time taken to cover 120 km = 120/60 = 2h
? The time, at which both the trains will meet, is 2 h after second train left i.e., 9 : 00 am + 2h = 11 : 00 am
Let x be the length of the standing train
? Speed of the train = (500 + x)/20
? 100 x (5/18) = (500 + x)/20
? 500 + x = (100 x 5 x 20)/18
? 500 + x = 555.56
? x = 555.56 - 500 = 55.56 m
Relative speed = (32 + 40) = 72 km/h = (72 x 5/18) m/s = 20 m/s
? Length of train = (20 x 6) = 120 m
Total distance to be traveled = 121 + 99 = 220 m
Relative speed = Sum of speeds = 72 km/h
= 72 x (5/18) = 20 m/s
? Required time = 220/20 = 11s
Let length of the train be x m.
Relative length of the train = (x + 600) m
According to the question,
(x + 600)/30 = 30
? x + 600 = 900
? x = 900 - 600 = 300 m
Let the speed of the train be V
According to the question.
(V + 10) x 12 = (V + 20) x 10
? 6V + 60 = 5V + 100
? x = 100 - 60 = 40 m/s
? Length of the train = (V + 10) x 12
= (40 + 10) x 12 = 600 m
Let the length of another train be L meters.
Their relative speed = (62 + 40) km/hr = 102 x (5/18) = (85/3) m/sec
? 250 + L/(85/3) = 18
? 3(250 + L)/85 = 18
? 250 + L = 510
? L = 260
? Length of another train = 260 meters
Relative speed of the train
= (70 - 10)
= 60 km/hr
= (60 x 5/18)
= 50/3) m/sec.
? Time taken by the train to pass the man
= (100 x 3/50) = 6 sec.
? Speed of the train = 54 x (5/18) m/sec = 15 m/sec
? Time taken by the train to cross the tunnel
= Time taken by it to cover (120 + 130) m
= (250/15) sec
= 162/3
Relative speed of both trains
= (50 - 30) = 20 km/hr
= 20 x (5/18) m/sec.
= (50/9) m/sec.
Let the length of the faster train be L
Then, (L x 9)/50 = 18
? L = (18 x 50)/9
= 100 meters
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