Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:

Question

Accepted Answer

Let the speed of the slower train be x m/sec. Then, speed of the faster train = 2x m/sec. Relative speed = (x + 2x) m/sec = 3x m/sec. ∴<…

=	❨	50	x	18	❩km/hr
		3		5

∴	(100 + 100)	= 3x
	8

⟹ x =	25	.
	3

Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:

Discussion & Comments