Question 1

A 150 m long train crosses another 210 m long train running in the opposite direction in 10.8 seconds. If the shorter train crosses a pole in 12 seconds, what is the speed of longer train ?

Accepted Answer

Total distance = 150 + 210 = 360 mts Time taken to cross each other when moving in opposite direction = 10.8 sec Relative speed of trains = (350/10.8) x 18/5 = 3600/30 = 120 kmph Speed of shorter train = (150/12) x 18/5 = 45 kmph Hence, speed of longer train = 120 - 45 = 75 kmph.

Question 2

An express train takes 4 seconds to enter tunnel which is 1 km long. If it is traveling at 108 km an hour, how long will it take to pass completely through the tunnel ?

Accepted Answer

Speed = 108 km/hr enter a tunnel,, means that the train covers a distance equal to its own length so (108 x 5/18) = x/4 where x= length of train hence x = 120 mtrs to pass completely train has to travel a distance = (x + tunnel length) that is 1120 mtrs. so (1120/t) = (108x5/18) t = 37.33 sec

Question 3

A train for Fathehpur leaves for every 2 hrs 30 min from Agra station. An announcement was made that train left 37 mins ago and next train comes at 17:00hrs. At what time was the announcement made ?

Accepted Answer

Next train comes at 17:00 hrs. So, last train will be = 17:00hrs - 2:30hrs = 14:30hrs Announcement made after 37 min of the last train. S0, 14:30hrs + 00:37 min = 15:07 hrs.

Question 4

How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction ?

Accepted Answer

The distance to be covered = Sum of their lengths = 200 + 300 = 500 m. Relative speed = 72 -36 = 36 kmph = 36 x 5/18 = 10 mps. Time required = d/s = 500/10 = 50 sec.

Question 5

A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?

Accepted Answer

Speed = 78 x 5/18 = 65/3 m/sec. Time = 1 min = 60 sec. Let the length of the train be x meters. Then, (900 + x)/60 = 65/3 x = 400 m.

Question 6

A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?

Accepted Answer

Total time taken = k/40 + 2k/20 hours = 5k/40 = k/8 hours Average speed = 3k/(k/8) = 24 kmph.

Question 7

Two trains, one from Hyderabd to Bangalore and the other from Bangalore to Hyderabad, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is ?

Accepted Answer

Let us name the trains as A and B. Then, (A's speed) : (B's speed) = √b : √a = √16 : √9 = 4:3

Question 8

The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is

Accepted Answer

Let the length of the brigade is x mts Then Distance = 130 + x mts given speed = 45 kmph = 45 x5/18 m/s Time = 30 sec T = D/S => 30 = 130+x/(45x5/18) => x = 245 mts.

Question 9

Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ?

Accepted Answer

Let the length of the stationary train Y be LY Given that length of train X, LX = 300 m Let the speed of Train X be V. Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively. => 300/V = 25 ---> ( 1 ) (300 + LY) / V = 60 ---> ( 2 ) From (1) V = 300/25 = 12 m/sec. From (2) (300 + LY)/12 = 60 => 300 + LY = 60 (12) = 720 => LY = 720 - 300 = 420 m Length of the stationary train = 420 m

Question 10

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train?

Accepted Answer

We know that, Speed = Distance/time Let the speed of the train be = x kmph NORMAL SPEED SPEED 5 KMPH MORE Distance = 360 Km Distance =360 speed = X Kmph Speed = (x+5) Time =360/X Time =360/(x+15) For the same journey if the speed increased 10 kmph more it will take 1 hour less Time with original speed - time with increased speed = 1 => (360/x) - (360/x+10) = 1 => (360(x+5)-360x)/x(x+5) =1 => 360X + 1800 -360X = X(X+5) => X^2 + 5x - 1800 = 0 X = 40 or -45 X cannot be negetive value X = 40 kmph.

Question 11

Two trains are moving in the opposite direction at speed of 30 km/hr and 45 km/hr respectively, whose lengths are 450 m and 550 m respectively. What is the time taken (in seconds) by slower train to cross the faster train?

Accepted Answer

48

Question 12

The time taken by a train 160 m long, running at 72 km/hr, in crossing an electric pole is

Accepted Answer

8 sec

Question 13

Excluding stoppages, the speed of a train is 120 kmph and including stoppages, it is 50 kmph. For how many minutes does the train stop per hour?

Accepted Answer

35

Question 14

A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ?

Accepted Answer

Let the original speed and time is S and T then distance = S x T Now the speed changes to 2/3S and T is T+20 As the distance is same S x T = 2/3Sx(T+20) solving this we get t = 40 minutes =40/60 = 2/3 hour

Question 15

A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ?

Accepted Answer

Speed of train relative to jogger = 45 - 9 = 36 km/hr. = 36 x 5/18 = 10 m/sec. Distance to be covered = 260 + 140 = 400 m. Time taken = 400/10 = 40 sec.

Question 16

Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is ?

Accepted Answer

Relative speed = 60 + 90 = 150 km/hr. = 150 x 5/18 = 125/3 m/sec. Distance covered = 1.10 + 0.9 = 2 km = 2000 m. Required time = 2000 x 3/125 = 48 sec.

Question 17

A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train ?

Accepted Answer

Relative speed = 120 + 80 = 200 km/hr. = 200 x 5/18 = 500/9 m/sec. Let the length of the other train be L mts. Then, (L + 260)/9 = 500/9 => L = 240 mts.

Question 18

Two trains move from stations M and N. Both trains move towards each other at speeds of 54 km/hr and 63 km/hr respectively. When they meeteach other, the second train has travel 100 km more than the first. What is the distance (in km) between M and N

Accepted Answer

1300

Question 19

A train takes 10 sec to cross a bridge of length 100 m travelling at 90 kmph. Find the length of the train in meters.

Accepted Answer

150

Question 20

5 hrs after a goods train passed a station, another train travelling at a speed of 70 km/hr following that goods train passed through that station. If after passing the station the train overtakes the goods train in 9 hours. What is the speed of the…

Accepted Answer

45 km/hr

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