Difficulty: Medium
Correct Answer: All of the above
Explanation:
Introduction / Context:
Water hammer is a classic unsteady-flow phenomenon in hydraulics. When a valve is closed or a pump trips, the flowing water column is suddenly decelerated, generating pressure waves that can far exceed normal steady-state pressures. Understanding what controls the surge magnitude is essential for safe pipeline design, surge-tank sizing, and valve-closure specifications.
Given Data / Assumptions:
Concept / Approach:
The Joukowsky relation gives the ideal instantaneous surge: Δp = ρ c ΔV. The wave speed c depends on bulk modulus of water, pipe wall modulus, diameter, and wall thickness. The resulting maximum pressure rise also depends on valve-closure time relative to the pipe period (2L/c) and on reflections governed by pipeline length and end conditions.
Step-by-Step Solution:
Verification / Alternative check:
Compare quick vs slow closure using method of characteristics: shorter closure yields higher initial surge; more elastic pipes reduce c, reducing Δp for the same ΔV.
Why Other Options Are Wrong:
Each single factor (a, b, c, d) affects the surge, but not exclusively. The correct comprehensive choice is that all listed factors contribute.
Common Pitfalls:
Ignoring pipe-wall elasticity; assuming only valve speed matters; neglecting reflections that can compound pressures at tees or dead ends.
Final Answer:
All of the above
Discussion & Comments