Source modeling: Does a practical (real-world) voltage source always include a nonzero internal resistance when represented for circuit analysis?

Difficulty: Easy

Correct Answer: True

Explanation:


Introduction / Context:
No physical source can maintain an absolutely constant terminal voltage under all loads. To capture real behavior (voltage sag and power loss), practical voltage sources are modeled with a series internal resistance.


Given Data / Assumptions:

  • Practical voltage source with finite energy and non-ideal regulation.
  • Internal resistance Rs is small but nonzero.
  • Load connected across the source terminals.


Concept / Approach:

The Thevenin model represents a practical voltage source as an ideal source Vs in series with an internal resistance Rs. Under load, the terminal voltage drops: V_terminal = Vs − I_load * Rs. This explains regulation limits and heat dissipation inside the source.


Step-by-Step Solution:

Assume a load drawing current I_load.Voltage at the terminals: V_terminal = Vs − I_load * Rs.Power lost internally: P_internal = I_load^2 * Rs.Consequently, Rs must be nonzero to reflect real behavior; ideal sources use Rs = 0 for analysis convenience.


Verification / Alternative check:

Measure open-circuit voltage (no load) and then loaded voltage. The drop from open-circuit to loaded conditions implies a finite internal resistance that can be estimated by Rs ≈ (V_oc − V_load) / I_load.


Why Other Options Are Wrong:

  • Regulated supplies approximate low Rs but never exactly zero.
  • Both AC and DC sources exhibit non-idealities; the model applies broadly.
  • Internal resistance exists across operating currents, not only at high load.


Common Pitfalls:

Assuming data-sheet “tight regulation” implies zero Rs. It only means Rs is small over a specified load range.


Final Answer:

True

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