Thevenin voltage definition: The Thevenin equivalent voltage VTH equals the open-circuit terminal voltage (not the short-circuit voltage). True or false?

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Thevenin and Norton theorems are dual tools for simplifying linear networks. Correctly identifying VTH and IN is essential to avoid modeling errors. This statement tests whether you can distinguish open-circuit from short-circuit measurements in forming equivalents.



Given Data / Assumptions:

  • We want the Thevenin equivalent at a pair of terminals.
  • All components are linear; dependent sources may be present.
  • Phasor impedances may be used for AC, but the definitions of VTH and IN remain the same.


Concept / Approach:

Thevenin equivalent voltage VTH is the open-circuit terminal voltage Voc with the load removed. Norton equivalent current IN is the short-circuit current Isc across the terminals. The Thevenin/Norton impedances are identical and satisfy ZTH = Voc / Isc if both quantities are defined and linearity holds.



Step-by-Step Solution:

Remove the load to measure Voc ⇒ VTH = Voc.Short the terminals to measure Isc ⇒ IN = Isc.Find ZTH by deactivating independent sources or using ZTH = Voc / Isc.Construct Thevenin: VTH in series with ZTH; Norton: IN in parallel with ZN where ZN = ZTH.


Verification / Alternative check:

Compute the terminal V–I relation with the derived VTH and ZTH and compare with the original circuit for two distinct loads. Matching results verify that VTH was correctly taken as the open-circuit voltage, not the short-circuit value.



Why Other Options Are Wrong:

  • Choosing “True” confuses the short-circuit metric with VTH. The short-circuit quantity corresponds to Norton current, not Thevenin voltage.


Common Pitfalls:

Accidentally deactivating dependent sources when finding ZTH; use a test source method if needed. Also, forgetting that power cannot be directly superposed when computing equivalents.



Final Answer:

False

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