Source transformation principle: Is it impossible to convert between an ideal voltage source with series resistance and an equivalent current source with parallel resistance (and vice versa)?

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Source transformations are a powerful analysis tool, allowing engineers to replace a Thevenin source with its Norton equivalent, simplifying circuit calculations without changing external terminal behavior.


Given Data / Assumptions:

  • Thevenin form: ideal voltage source Vth in series with Rth.
  • Norton form: ideal current source In in parallel with Rn.
  • Equivalence is at the same two external terminals and for linear bilateral elements.


Concept / Approach:

The conversions are defined by In = Vth / Rth and Rn = Rth. Conversely, Vth = In * Rn. The two models produce the same open-circuit voltage, short-circuit current, and terminal V–I relation, ensuring equivalence.


Step-by-Step Solution:

Start with Vth in series with Rth.Compute the short-circuit current: Isc = Vth / Rth → define In = Isc.Retain the same resistance: Rn = Rth in parallel with In.Verify: Open-circuit voltage Voc = Vth = In * Rn; short-circuit current Isc = Vth / Rth = In.


Verification / Alternative check:

Plot the terminal V–I characteristic; both models yield V = Vth − I * Rth = In * Rn − I * Rn, which are algebraically identical when Rn = Rth and In = Vth / Rth.


Why Other Options Are Wrong:

  • Equivalence does not require zero resistance; it requires the stated relationships.
  • Linearity is the key assumption; nonlinearity is not a requirement.
  • The method applies to both DC and AC (using phasors/impedances).


Common Pitfalls:

Forgetting to keep the resistance the same in both forms, or mixing up open-circuit and short-circuit conditions when deriving In or Vth.


Final Answer:

False

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