Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:
The hallmark of a P–N junction is the formation of an internal potential barrier that opposes majority-carrier diffusion. This barrier explains diode rectification and underpins transistor action. Interpreting the statement correctly requires noting operating conditions (equilibrium, forward bias, reverse bias).
Given Data / Assumptions:
Concept / Approach:
At equilibrium, diffusion of majority carriers (electrons from n to p, holes from p to n) creates a space-charge region with an electric field that drives drift in the opposite direction. The resulting built-in potential V_bi forms a barrier impeding further majority-carrier diffusion. Under forward bias, the external source reduces this barrier, allowing significant current; under reverse bias, the barrier increases, suppressing majority-carrier flow and leaving only a small minority-carrier current until breakdown.
Step-by-Step Solution:
Verification / Alternative check:
Diode I–V shows negligible current for reverse bias before breakdown and large current for forward bias once overcoming the barrier (~0.3 V Ge, ~0.7 V Si at room temperature for typical small diodes).
Why Other Options Are Wrong:
Common Pitfalls:
Forgetting that minority carriers can still traverse the junction; conflating “barrier” with an absolute block rather than an energy threshold modified by bias.
Final Answer:
Correct
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