Difficulty: Easy
Correct Answer: False
Explanation:
Introduction / Context:Planck’s law gives the spectral distribution of emissive power of a perfect black body. Real (coloured) bodies deviate from blackbody behaviour and are described through emissivity.
Given Data / Assumptions:
Concept / Approach:For real bodies, spectral emissive power E(λ, T) = ε(λ, T) * E_b(λ, T), where E_b is given by Planck’s law. Thus, Planck’s law applies to the ideal blackbody spectrum, while real bodies follow it only after scaling by their emissivity function.
Step-by-Step Solution:
State Planck’s law as the blackbody spectral distribution.Introduce emissivity ε(λ, T) for real surfaces.Relate real-body emission to blackbody by multiplication with ε(λ, T).Conclude that the statement “holds good for all coloured bodies” is false.Verification / Alternative check:Kirchhoff’s law links emissivity and absorptivity; experimental spectra for paints, metals, and ceramics confirm departures from the blackbody curve.
Why Other Options Are Wrong:Restrictions to vacuum, temperature range, or material do not convert a real body into a black body; emissivity remains less than unity and wavelength dependent.
Common Pitfalls:Using blackbody tables directly for engineering surfaces without applying emissivity corrections leads to significant errors.
Final Answer:False
Discussion & Comments