Difficulty: Easy
Correct Answer: All of the above
Explanation:
Introduction / Context:
Lenses appear in many civil and surveying instruments (levels, theodolites, total stations) and also in drafting aids and optical sights. Understanding “power” clarifies how focal length relates to instrument magnification and how compound eyepieces or lens groups behave when combined. This question checks three foundational facts: definition of power, its unit, and how powers add for thin lenses in contact.
Given Data / Assumptions:
Concept / Approach:
Lens power P quantifies refracting strength. By definition, P = 1 / f when f is in meters. The SI unit is diopter, written D or m^-1. For thin lenses placed in contact, the equivalent power is the sum of individual powers: P_total = P1 + P2 + …, which is widely used in designing eyepieces and objective–eyepiece combinations in surveying telescopes.
Step-by-Step Solution:
Verification / Alternative check:
Optics texts for engineering instruments adopt diopters for quick mental calculation: for example, a 0.25 m focal length lens has power 4 D. Stacking two 2 D thin lenses gives 4 D total (approximate) when in contact, matching P_total = P1 + P2.
Why Other Options Are Wrong:
Common Pitfalls:
Using focal length in centimeters when calculating diopters; forgetting that power addition presumes thin lenses in contact (finite separations demand more detailed matrix methods); confusing magnification with power (they are related but not identical).
Final Answer:
All of the above
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