Difficulty: Easy
Correct Answer: all inputs are LOW
Explanation:
Introduction / Context:
NOR gates are universal building blocks. Knowing precisely when their outputs go HIGH is vital for interpreting logic equations and designing control signals.
Given Data / Assumptions:
Concept / Approach:
Since OR outputs HIGH if any input is HIGH, its complement (NOR) outputs HIGH only in the single case where every input is LOW and the OR output would be LOW.
Step-by-Step Solution:
OR truth: any 1 among inputs → output 1.NOR truth: invert the OR result.Therefore, NOR outputs 1 only when inputs are all 0.
Verification / Alternative check:
Construct a two-row argument: OR(0,0,...,0) = 0 → NOR = 1; any other case OR = 1 → NOR = 0.
Why Other Options Are Wrong:
“All inputs HIGH” / “any input HIGH”: those make OR = 1 → NOR = 0.“Any input LOW”: includes mixed cases where other inputs may be HIGH; NOR would be LOW then.
Common Pitfalls:
Confusing NOR with NAND; NAND outputs LOW only when all inputs are HIGH, whereas NOR outputs HIGH only when all inputs are LOW.
Final Answer:
all inputs are LOW
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