One-third of a two-digit number exceeds one-fourth of its successive number by 1. The number is
Aptitude
Problems on Numbers
Difficulty: Medium
Choose an option
-
A12
-
B15
-
C18
-
D21
Answer
Correct Answer: 15
Explanation
### Concept & Logic
This problem defines a relationship between a number and its successive (next consecutive) integer using fractional parts. "Exceeds" means the difference between the larger and smaller value is 1.
$$ \frac{x}{3} - \frac{x + 1}{4} = 1 $$
### Step-by-Step Solution
* Let the required two-digit number be $x$.
* Its successive number is $x + 1$.
* One-third of the number is $\frac{x}{3}$.
* One-fourth of its successive number is $\frac{x + 1}{4}$.
* According to the problem, the first quantity exceeds the second by 1:
$$ \frac{x}{3} - \frac{x + 1}{4} = 1 $$
* Find a common denominator (12) for the left side:
$$ \frac{4x - 3(x + 1)}{12} = 1 $$
* Distribute the negative sign carefully:
$$ \frac{4x - 3x - 3}{12} = 1 $$
$$ \frac{x - 3}{12} = 1 $$
* Solve for $x$:
$$ x - 3 = 12 $$
$$ x = 15 $$
### Exam Strategy & Shortcut
Use **Option Elimination**, which is incredibly fast for small integers. You need a number that is easily divisible by 3, and whose successor is divisible by 4.
* Check (a) 12: Successor is 13 (not cleanly divisible by 4). Skip.
* Check (b) 15: One-third is $15 \div 3 = 5$. Successor is 16. One-fourth is $16 \div 4 = 4$. Difference is $5 - 4 = 1$. Matches perfectly!
You can arrive at the answer in under 10 seconds without algebra.
### Common Pitfall
A frequent algebraic error is forgetting to distribute the negative sign when finding the common denominator. Writing $4x - 3x + 3$ instead of $4x - 3x - 3$ will completely derail the final answer.
### Final Answer
**Therefore, the correct answer is 15.**