Find the odd 4-letter block (−2, −2, +6 signature): Choose the option that does not follow the “−2, −2, +6” pattern.

Difficulty: Medium

Correct Answer: PNKR

Explanation:

Introduction / Context:When several items share the same three-step signature, the outlier is the one whose differences do not match the template. Here the template is two equal backward steps followed by a forward jump restoring balance.

Given Data / Assumptions:

  • LJHN: L→J (−2), J→H (−2), H→N (+6) → fits.
  • FDBH: F→D (−2), D→B (−2), B→H (+6) → fits.
  • SQOU: S→Q (−2), Q→O (−2), O→U (+6) → fits.
  • PNKR: P→N (−2), N→K (−3), K→R (+7) → breaks the pattern.

Concept / Approach:Compute successive differences and compare against the “−2, −2, +6” rule. The item that deviates in magnitude is the odd one out.

Step-by-Step Solution:

1) Calculate three differences for each option.2) Match them to (−2, −2, +6).3) PNKR yields (−2, −3, +7), hence is the outlier.

Verification / Alternative check:Reverse the sequence to check for symmetry; PNKR still fails to align.

Why Other Options Are Wrong:They conform exactly to the intended signature.

Common Pitfalls:Ensure sign and magnitude are both verified; small slips easily invert conclusions.

Final Answer:PNKR

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