Find the odd 4-character pattern (+2, +1, +2 across cases): Pick the item that does not follow “+2, +1, +2”.
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ABdEg
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BPrSu
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CKmNp
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DTwXz
Answer
Correct Answer: TwXz
Explanation
Introduction / Context:Alternating-case sequences still map to the same alphabetical index. Here, most items step +2, then +1, then +2. The outlier changes the first step magnitude, which exposes it immediately when the arithmetic is checked.
Given Data / Assumptions:
- BdEg: B→d (+2), d→E (+1), E→g (+2) → fits.
- PrSu: P→r (+2), r→S (+1), S→u (+2) → fits.
- KmNp: K→m (+2), m→N (+1), N→p (+2) → fits.
- TwXz: T→w (+3), w→X (+1), X→z (+2) → first step +3, so breaks the rule.
Concept / Approach:Ignore case, compute three successive differences, and match against the template (+2, +1, +2). The one with a different first step is odd.
Step-by-Step Solution:
1) Translate letters to indices (A=1…Z=26).2) Compute differences for each hop.3) “TwXz” starts with +3 instead of +2 → outlier.Verification / Alternative check:Visual spacing on an alphabet line shows a wider first gap only for the outlier.
Why Other Options Are Wrong:They maintain the same +2, +1, +2 cadence.
Common Pitfalls:Do not be distracted by wrap-around concerns; none of the conforming items require wrapping.
Final Answer:TwXz