Among the alphanumeric codes 2T0, 1R8, 2Y4 and 1P6, which one does not belong to the group based on the relationship between the digits and the letter's position in the alphabet?

Difficulty: Easy

Correct Answer: 2Y4

Explanation:


Introduction / Context:
This question uses alphanumeric codes where each code consists of a digit, a letter, and another digit. The task is to identify the odd man out, that is, the code that does not follow the same rule as the others. Such problems test both number sense and familiarity with alphabetical positions.


Given Data / Assumptions:
The codes given are: 2T0, 1R8, 2Y4 and 1P6. We assume that each letter corresponds to its position in the English alphabet: A = 1, B = 2, C = 3, ..., Z = 26. We also assume there is a logical relationship between the two digits and the letter in each code.


Concept / Approach:
A natural pattern to test is whether the letter's position equals the two-digit number formed by putting the first and last digits together. In other words, for 2T0 we check whether T is the 20th letter; for 1R8 we check whether R is the 18th letter, and so on. If three codes satisfy this property and one does not, that one will be the odd man out.


Step-by-Step Solution:
Step 1: Evaluate 2T0. Combine the digits 2 and 0 to get 20. The letter T is indeed the 20th letter of the alphabet, so 2T0 follows the pattern.Step 2: Evaluate 1R8. Combine the digits 1 and 8 to get 18. The letter R is the 18th letter, so 1R8 also follows the same rule.Step 3: Evaluate 1P6. Combine the digits 1 and 6 to get 16. The letter P is the 16th letter, so 1P6 again fits the pattern.Step 4: Evaluate 2Y4. Combine the digits 2 and 4 to get 24. The letter Y is the 25th letter of the alphabet, not the 24th. Thus, 2Y4 does not satisfy the rule.


Verification / Alternative check:
We can quickly list the positions of the letters: R is 18, P is 16, T is 20 and Y is 25. The numeric parts of the codes are 20, 18, 24 and 16, from 2T0, 1R8, 2Y4 and 1P6 respectively. Only in the case of 2Y4 is the numeric value (24) not equal to the alphabetical position (25). Therefore, 2Y4 is clearly the only code that breaks the pattern.


Why Other Options Are Wrong:
2T0, 1R8 and 1P6 each perfectly obey the rule “letter position = two-digit number formed by the outer digits.” Choosing any of these as the odd man out would ignore this neat and consistent property, so they cannot be considered correct answers.


Common Pitfalls:
Some candidates may focus on the sum or difference of the digits, or look for divisibility properties, and miss the simple relation to alphabet positions. Another mistake is to miscount letter positions (for example, confusing R with the 17th letter instead of the 18th). Carefully counting from A = 1 to the target letter avoids this error.


Final Answer:
The only code that does not satisfy the digit-to-letter position rule is 2Y4.

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