In the following question, select the odd letter from the alternatives given below. Three letters are vowels, while one is a consonant. Identify the letter that does not belong to the same group. (A) B (B) N (C) P (D) W (E) A

Introduction / Context:
This odd-letter question is based on a simple classification property. A common approach in letter-based aptitude questions is to classify letters by vowel/consonant, even/odd alphabet position, or shape. Here, the cleanest dominant rule is based on alphabet position parity (even/odd).

Given Data / Assumptions:

• Alphabet positions: A=1, B=2, ..., Z=26.
• Even position letters have positions divisible by 2.
• Odd position letters have positions not divisible by 2.

Concept / Approach:
Compute the alphabet position of each letter and check whether most of them share the same parity (even or odd). The letter that differs is the odd one out.

Step-by-Step Solution:

Verification / Alternative check:
Among the original four alternatives B, N, P, W: B(2), N(14), and P(16) are all even-position letters, while W(23) is odd-position. Therefore W breaks the shared even-position pattern and is the odd one out in the intended set.

Why Other Options Are Wrong:

Common Pitfalls:
Students often try vowel/consonant first, but all four original letters are consonants, so that does not help. Another pitfall is forgetting the letter positions (for example, mixing up N as 13 instead of 14). When vowel/consonant fails, position parity (even/odd) is a strong next check.

Final Answer:
W