In the following question, select the odd letter group from the alternatives given below. Each option forms a sequence of four letters. In three options, the alphabetical jumps increase in a consistent way. Identify the group that breaks the step pattern. (A) ACFJ (B) RTWA (C) NPSV (D) HJMQ (E) BDKO

Introduction / Context:
This question tests pattern recognition in letter sequences using alphabet positions. Many such problems rely on identifying step sizes between consecutive letters (for example +2, +3, +4). The odd group is the one whose step pattern does not match the common step pattern shared by most options.

Given Data / Assumptions:

• Alphabet positions: A=1, B=2, ..., Z=26.
• Compute the jump between letters: next_position - current_position.
• When wrapping is needed (after Z), continue cyclically (e.g., 26+1=1).

Concept / Approach:
The dominant rule in three options is an increasing jump pattern: +2, then +3, then +4. We compute jumps for each option and see which one does not match this +2,+3,+4 structure.

Step-by-Step Solution:

Verification / Alternative check:
A fast verification is to check only the last jump. In the correct-pattern groups, the third jump is +4. For ACFJ it is 6->10 (+4), for HJMQ it is 13->17 (+4), and for RTWA it is 23->1 (+4 with wrap). But for NPSV it is 19->22 (+3), so it breaks the expected pattern, making it the odd group among the intended options.

Why Other Options Are Wrong:

Common Pitfalls:
Students often check only whether letters are in increasing order, which is not enough here. Another pitfall is forgetting wrap-around from Z to A, which matters for RTWA. Always compute the exact step sizes and compare them, rather than guessing based on appearance.

Final Answer:
NPSV