Most economical trapezoidal channel section — identifying equivalent criteria: Which of the following conditions are satisfied by a hydraulically most economical trapezoidal open-channel section?

Civil Engineering Hydraulics Difficulty: Medium
Choose an option
  • A
    Half of the top width equals one of the sloping sides
  • B
    Hydraulic mean depth equals half the flow depth
  • C
    A semicircle drawn on the top width as diameter touches the three wetted sides
  • D
    All of these
  • E
    None of these

Answer

Correct Answer: All of these

Explanation

Introduction / Context:The “most economical” (best hydraulic) section minimizes wetted perimeter for a given area, thereby maximizing discharge for a given slope and roughness (or minimizing energy loss). For trapezoidal channels, several geometric conditions are equivalent indicators of this optimum shape.

Given Data / Assumptions:

  • Uniform, steady, open-channel flow.
  • Trapezoidal cross-section with base width b, side slope m:1, and depth y.
  • Optimization under constant area and slope (Manning/Chezy framework).

Concept / Approach:

For the most economical trapezoid, the condition is that the hydraulic radius R = A/P is maximized. This leads to canonical geometric results that can be expressed in multiple equivalent forms, including relationships among top width, side lengths, and inscribed semicircle tangency to the wetted boundary.

Step-by-Step Solution:

Start from optimum condition: d(P)/d(variable) = 0 at fixed A or use calculus of variations.Obtain standard results: half of top width equals sloping side length; side slopes meet the base so that the wetted perimeter is minimized.Show hydraulic mean depth R equals y/2 at optimum, implying efficient conveyance.Geometric construction: semicircle with diameter as top width tangent to wetted boundary confirms symmetry of distances.

Verification / Alternative check:

Textbook derivations using Chezy or Manning demonstrate identical optimum conditions; numerical examples confirm lower P for the same A at the optimum.

Why Other Options Are Wrong:

Here, (a), (b), and (c) are each true descriptors; thus selecting only one would be incomplete. The correct comprehensive choice is (d).

Common Pitfalls:

Confusing the most economical rectangle (b = 2y) with trapezoid conditions; overlooking that several geometric tests are equivalent at optimum.

Final Answer:

All of these

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