Compute void ratio from mass–volume data: A moist soil sample has total mass 108 g and volume 60 cm³. Its water content is 25% and specific gravity of solids G = 2.52. Determine the void ratio e.

Difficulty: Medium

Correct Answer: 0.75

Explanation:


Introduction / Context:
This numerical problem uses basic phase relationships to compute void ratio e from measured mass, volume, water content, and specific gravity. It illustrates how laboratory data translate to structure-defining parameters like e that control compressibility and permeability.


Given Data / Assumptions:

  • Total mass M = 108 g, total volume V = 60 cm³.
  • Water content w = 25% = 0.25 (decimal).
  • Specific gravity of solids G = 2.52; take density of water = 1 g/cm³.


Concept / Approach:
Water content w = Mw / Ms ⇒ M = Ms + Mw = Ms (1 + w). Solve for solids mass Ms, then compute volume of solids Vs = Ms / (G * ρw). With total volume V known, void volume is Vv = V − Vs. Finally, e = Vv / Vs.


Step-by-Step Solution:

Compute Ms: Ms = M / (1 + w) = 108 / 1.25 = 86.4 g.Compute Vs: Vs = Ms / (G * ρw) = 86.4 / (2.52 * 1) ≈ 34.2857 cm³.Compute Vv: Vv = V − Vs = 60 − 34.2857 ≈ 25.7143 cm³.Compute e: e = Vv / Vs ≈ 25.7143 / 34.2857 ≈ 0.75.


Verification / Alternative check:
Check porosity n = e / (1 + e) ≈ 0.75 / 1.75 ≈ 0.429 (about 43%), a reasonable value for a moist, medium-density fine-grained soil.


Why Other Options Are Wrong:

  • 0.55, 0.65, 0.80, 0.95: Do not match the computed ratio based on mass–volume consistency.


Common Pitfalls:
Using w in percent without converting to decimal; forgetting that total volume V = Vs + Vv even in partially saturated states; using G incorrectly (it multiplies ρw).


Final Answer:
0.75

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