Critical Hydraulic Gradient for Quicksand – Compute Using Gs and Porosity For a sand with specific gravity of soil solids Gs = 2.696 and porosity n = 44% (loose state), determine the critical hydraulic gradient i_c for the onset of quick (boiling) condition.
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A0.91
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B0.92
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C0.93
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D0.94
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E0.95
Answer
Correct Answer: 0.95
Explanation
Introduction / Context:The critical hydraulic gradient i_c marks the threshold for boiling (quicksand) in cohesionless soils under upward seepage. Designers use i_c to check against piping at exits beneath hydraulic structures and to plan safe dewatering around excavations below the water table.
Given Data / Assumptions:
- Specific gravity of solids Gs = 2.696.
- Porosity n = 44% = 0.44.
- Water unit weight is reference; formula based on submerged weight balance.
Concept / Approach:
For upward seepage, the critical gradient is i_c = (Gs − 1) / (1 + e), where e is void ratio. Convert porosity to void ratio by e = n / (1 − n). If the applied gradient equals or exceeds i_c, the seepage force cancels the submerged unit weight, making σ′ → 0 (boiling condition).
Step-by-Step Solution:
Compute void ratio: e = 0.44 / 0.56 = 0.785714.Compute numerator: Gs − 1 = 2.696 − 1 = 1.696.Compute denominator: 1 + e = 1 + 0.785714 = 1.785714.i_c = 1.696 / 1.785714 ≈ 0.9496 ≈ 0.95.Verification / Alternative check:
Check reasonableness: For typical sands with e around 0.7–0.9 and Gs near 2.65, i_c usually lies near 1.0; the computed value 0.95 fits expectations.
Why Other Options Are Wrong:
0.91–0.94 underestimate the ratio slightly given the stated porosity and Gs; 0.95 best matches the computed i_c.
Common Pitfalls:
Using n instead of e directly in the denominator; forgetting to convert percent to fraction; confusing Gs with unit weight ratio γ_s/γ_w (they are consistent here since γ_w is the reference).
Final Answer:
0.95