State Variables of a Perfect (Ideal) Gas — Which Variables Govern Its Physical Properties? Identify the set of variables that control the thermodynamic state and physical properties of a perfect (ideal) gas in equilibrium.

Difficulty: Easy

Correct Answer: all of these

Explanation:


Introduction / Context:
State description for a simple compressible substance (such as an ideal gas) requires identifying independent variables that uniquely fix the state. For ideal gases, the classic triad is pressure, volume, and temperature.


Given Data / Assumptions:

  • Simple, single-phase ideal gas.
  • Equilibrium (no significant gradients).
  • Fixed composition (molar mass constant).


Concept / Approach:
The ideal-gas equation p * V = m * R * T relates pressure p, volume V, and temperature T for a fixed mass m and gas constant R. Any two independent variables determine the third. Together, they govern density, specific volume, internal energy (through T), and other derived properties.


Step-by-Step Solution:
Recognize the equation of state: p * V = m * R * T.For fixed m and R, two independent variables among p, V, T determine the state.Hence, the full set p, V, and T control the gas’s physical state and properties.


Verification / Alternative check:
Experimental P–V–T surfaces for gases confirm that specifying two variables (e.g., p and T) fixes specific volume v via v = R * T / p.


Why Other Options Are Wrong:
Each of A, B, or C alone is incomplete; all three together constitute the governing variables.


Common Pitfalls:
Using Celsius rather than Kelvin for ideal-gas calculations; forgetting composition must be fixed for R to be constant.


Final Answer:
all of these

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