Difficulty: Easy
Correct Answer: A Joule (Brayton) cycle consists of two constant volume and two isentropic processes.
Explanation:
Introduction / Context:
Recognizing the signature process sets of common thermodynamic cycles is essential for analyzing engines and gas turbines. This question asks you to identify the incorrect description among several standard cycles.
Given Data / Assumptions:
Concept / Approach:
The Otto cycle (spark-ignition) has two isentropic (compression/expansion) and two constant-volume (heat addition/rejection) processes. The Ericsson cycle has two isothermal and two constant-pressure processes with regeneration. The Joule (Brayton) cycle, however, comprises two isentropic and two constant-pressure processes, not constant volume. Therefore, the statement assigning constant-volume processes to the Joule cycle is incorrect.
Step-by-Step Solution:
Check Otto: CV + CV + two isentropes ⇒ correct.Check Ericsson: isothermals + CP with regeneration ⇒ correct.Check Joule/Brayton: should be CP + CP + two isentropes; the given statement says CV, which is wrong.Therefore, option A is the incorrect statement.
Verification / Alternative check:
Component mapping: compressor/turbine are isentropic; combustor/exhaust are nearly constant-pressure → matches Brayton, confirming option A is wrong.
Why Other Options Are Wrong:
Option D (“all of the above”) is not correct because B and C are true; only A is incorrect.
Common Pitfalls:
Confusing Otto (CV heat addition) with Brayton (CP heat addition); assuming “all of the above” when only one statement is actually wrong.
Final Answer:
A Joule (Brayton) cycle consists of two constant volume and two isentropic processes.
Discussion & Comments