Poisson’s ratio under tension vs. compression:\nA steel bar (2 m × 20 mm × 10 mm) carries 2 kN in tension or in compression within the elastic range. How does Poisson’s ratio in tension compare with that in compression?

Difficulty: Easy

Correct Answer: equal to

Explanation:


Introduction / Context:
Poisson’s ratio ν is a material constant in linear elasticity that relates lateral strain to axial strain. For small strains within the elastic limit, ν is independent of whether the load is tensile or compressive.


Given Data / Assumptions:

  • Same prismatic steel bar loaded by ±2 kN (tension or compression).
  • Material behavior in the linear-elastic range without plasticity or damage.
  • Isotropy and homogeneity assumed.


Concept / Approach:
By definition, ν = − ε_lateral / ε_axial in the elastic regime. For isotropic materials, ν is a constant for a given material over small strains, independent of load sign. Only once plasticity, microcracking, or other nonlinear effects occur could an apparent asymmetry develop, which is outside the problem scope.


Step-by-Step Solution:

Under tension: ε_axial > 0, ε_lateral < 0 ⇒ ν = − ε_lat / ε_axial.Under compression: ε_axial < 0, ε_lateral > 0 ⇒ ν = − ε_lat / ε_axial.In both cases, the magnitude of the ratio remains the same in linear elasticity.


Verification / Alternative check:
Standard elastic-constant relations (E, G, K, ν) and reciprocity do not depend on load sign within the elastic domain; experimental handbooks report a single ν value for a material like steel (e.g., ~0.3).


Why Other Options Are Wrong:

  • “Less than/greater than” implies nonlinearity or damage not stated.
  • Dependence on bar dimensions or load magnitude conflicts with ν being an intrinsic material property.


Common Pitfalls:
Confusing elastic constants with geometric stiffness; assuming plastic effects at low loads; mixing up ν with lateral contraction per se.


Final Answer:
equal to

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