Plastic region behavior in tensile testing:\nBeyond the elastic limit on a stress–strain curve, how does tensile strain vary compared to applied stress?

Difficulty: Easy

Correct Answer: increases more quickly

Explanation:


Introduction / Context:
The stress–strain curve of ductile materials shows an elastic region (linear, Hookean) followed by a plastic region. Understanding how strain evolves relative to stress beyond the elastic limit is crucial for safe design and for predicting permanent deformations.


Given Data / Assumptions:

  • Standard uniaxial tensile test on a ductile metal specimen.
  • Observation focuses on the region beyond the elastic limit (onset of plasticity).
  • Monotonic loading; room temperature; engineering stress–strain definition.


Concept / Approach:
In the elastic region, stress is proportional to strain (σ = E ε). Once the elastic limit is exceeded, plastic deformation begins. Additional strain accrues at a faster rate for comparatively small increases in stress, especially near yield where the curve flattens (yield plateau in some steels).


Step-by-Step Solution:

Before yield: ε = σ / E (linear).At/after yield: curve deviates; large ε increment for small σ increment.Thus, strain increases more quickly than stress beyond elastic limit.


Verification / Alternative check:
Typical stress–strain plots for steels show a yield plateau or gradual hardening: significant strain develops with little to moderate stress increase, confirming the qualitative relationship.


Why Other Options Are Wrong:

  • Decreasing strain with increasing stress contradicts physical behavior.
  • “Remains proportional” is only valid in the elastic region, not beyond.


Common Pitfalls:
Confusing engineering and true stress–strain beyond necking; misreading the yield plateau as constant strain; assuming linearity throughout loading.


Final Answer:
increases more quickly

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