Nozzle exit velocity formula (steam): select the correct relation Let K be the nozzle efficiency (or nozzle coefficient) and hd be the enthalpy (heat) drop during expansion per kilogram. Choose the correct expression for the theoretical exit velocity V (m/s).
Mechanical Engineering
Steam Nozzles and Turbines
Difficulty: Easy
Choose an option
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AV = 44.72 × √(K × h<sub>d</sub>)
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BV = 44.72 × (K × h<sub>d</sub>)
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CV = 44.72 × √(h<sub>d</sub>/K)
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DV = 44.72 × (h<sub>d</sub>/K)
Answer
Correct Answer: V = 44.72 × √(K × h<sub>d</sub>)
Explanation
Concept/Approach
- From steady adiabatic nozzle energy balance: V ≈ √(2 × K × Δh) with Δh in J/kg.
- With Δh (kJ/kg), conversion gives V (m/s) = 44.72 × √(K × hd) (since √(2 × 1000) ≈ 44.72).
Final AnswerV = 44.72 × √(K × hd)